✔ 最佳答案
Let P (n) be the proposition (n+1)(n+2)(n+3).......(n+n) = 2n.1.3.5......(2n-1)
When n = 1,
L.H.S. = 1 + 1 = 2
R.H.S. = 21 = 2 = L.H.S.
Therefore P (1) is true.
Assume P ( k ) is true for some positive integers k.
i.e. (k+1)(k+2)(k+3).......(k+k) = 2k.1.3.5......(2k - 1)
When n = k + 1 ,
L.H.S. = (k+1+1)(k+2+1)(k+3+1).......(2k+ 2 – 2)(2k+ 2 – 1)( 2k + 2 )
= ( k + 1 )( k + 2 )( k + 3 )( k + 4 )……(2k)(2k+ 1)(2)
= 2k.1.3.5......(2k+1)(2)
= 2k+1.1.3.5......(2k+1)
R.H.S. = 2k.1.3.5......(2k+2-1)
= 2k+1.1.3.5......(2k+1)
= L.H.S.
Therefore P ( k + 1 ) is true.
By the principle of mathematical induction, P ( n ) is true for all positive integers n.