F.2----4題數學題

1. Convert 2E1(16) into a denary number.

2E1(16) = 2 x 162 + 14 x 16 + 1 x 1

= 737(10)



2. Convert 110110(2) into a denary number.

110110(2) = 1 x 25 + 1 x 24 + 0 x 23 + 1 x 22 + 1x 2 + 0 x 1

= 54(10)



3. Convert 37(10) into a binary number.

By division, the remainders arrange as 1, 0, 0, 1, 1 and 1.

So 37(10) = 100101(2)



4. Convert 444(10) into a hexadecimal number.

By division, the remainders arrange as 1, B and C.

So 444(10) = 1BC(16)

1) 2E1 (16) = 737 (10)
2) 110110 (2) = 54 (10)
3) 37 (10) = 100101 (2)
4) 444 (10) = 1BC (16)


補充:
denary number = 10 進制
binary number = 2 進制
hexadecimal number = 16 進制
() 內數字是代表?進制
例如:
444 (10) = 1BC (16)
即係10 進制既 444 = 16 進制既 1BC