英文maths.....

( 1 a ) Let the price of each apple be $ x and that of orange be $ y.

For Peter,

2x + 3y = 12 --- ( 1 )

For Mary,

4x + 2y = 16

2x + y = 8 --- ( 2 )

Solving ( 1 ) and ( 2 ),

x = 3 and y = 2

b ) John should pay = 3 x + 4y = 3 ( 3 ) + 4 ( 2 ) = $ 17

( 2 ) b : a = 2 : 3 and a : c = 1 : 2

So, b : a : c = 2 : 3 : 6

Then a : b : c = 3 : 2 : 6

( 3 ) A : 300 ( 4 / 15 ) = 80

B : 300 ( 5 / 15 ) = 100

C : 300 ( 6 / 15 ) = 120

1a)
x=apple, y= orange
2x+3y=12
4x+2y=16
2(12-3y)+2y = 16
24-6y+2y=16
8=4y
y=2
4x+2 (2)=16
4x=16-4
x=3
Apple is $3, orange is $2

b) John: 3x+4y=3 (3) + 4 (2) = $17

2)
a:c = 1:2 and b:a = 2:3,
a:b:c = 3:2:2x3 = 3:2:6

3)
A,B and Cshare 300 marbles in the ratio 4 : 5 : 6
A: 300 x 4 / (4+5+6) = 80
B: 300 x 5 / (4+5+6) = 100
C: 300 x 6 / (4+5+6) = 120

Question 1
Let apple = a
orange = b

(1) 2a+3b = 12
(2) 4a+2b = 16

From (1) a = 12-3b / 2

Input into (2)

4[(12-3b)/2] + 2b =16

2(12-3b) + 2b = 16

24-6b+2b = 16

24-4b = 16

24-16 = 4b

8 = 4b

b = 2

if you know b = 2, then input into (1)

a = 12-3(2) / 2

a = 3


Therefore Apple = $3 and Orange = $2



Question 2


a:c = 1:2

b:a = 2:3


a:b:c
1: 2
3:2
-------
3:2:6


Question 3

Let marble = a

4a+5a+6a = 300

15a = 300

a = 20

Therefore A can have 80 marbles,
B can have 100 marbles
C can have 120 marbles