trigonometry - - maths 問題

2007-07-18 7:23 am
0° < θ < 360°

A. 2 sin θ =1
_
B. √2 cos θ =1

回答 (3)

2007-07-18 7:39 am
A.
sin θ =1/2
θ = 30° & 150°

B.
cos θ =1/ √2
θ = 45° & 315°
2007-07-18 7:29 am
A)
sinθ = 1/2
θ = 30° or 150°

B)
cosθ = 1/√2
θ = 45° or 315°
2007-07-18 7:27 am
A.
θ = 30°, 150°
B.
θ = 45°, 315°
參考: my knowledge


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