✔ 最佳答案
x2 – (y - z)2
= [x + (y - z)][x – (y - z)]
= (x + y - z)(x – y + z)
(x + y + z)(x + y + z)
= x(x + y + z) + y(x + y + z) + z(x + y + z)
= x2 + xy + xz + xy + y2 yz + xz + yz + z2
= x2 + y2 + z2 + 2xy + 2yz + 2xz
[2x + (3y - 2)][2x – (3y - 2)]
= (2x)2 – (3y - 2)2
= 4x2 – (9y2 – 12y + 4)
= 4x2 – 9y2 + 12y – 4
證明(x + y)3 ≡ x3 + 3x2y + 3xy2 + y3
L.H.S.
= (x + y)3
= (x + y)(x + y)(x + y)
= [x(x + y) + y(x + y)](x + y)
= (x2 + 2xy + y2)(x + y)
= x2(x + y) + 2xy(x + y) + y2(x + y)
= x3 + x2y + 2x2y + 2xy2 + xy2 + y3
= x3 + 3x2y + 3xy2 + y3
= R.H.S.