2(x-2)^2=7
用因式分解點做??唔該哂~~~~~
因式分解??
2007-07-17 6:03 am
回答 (1)
2007-07-17 6:56 am
✔ 最佳答案
2(x-2)^2=72(x-2)^2 – 7 = 0
(x-2)^2 – (7/2) = 0
[x – 2 - √(7/2)][x – 2 + √(7/2)] = 0
x = 2 + √(7/2)
= 2 + √(14)/2 或
x = 2 - √(7/2)
= 2 - √(14)/2
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原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070716000051KK05193