Let p, q be conjugate exponents. Let a, b be any positive real numbers. Prove that
a^p b^q
ab ≤ ----- + -----
p q
This is trivially true for a = b = 0. Please give only the answer for positive part.
* I won't give any marks to someone who is giving pictorial answers, I will only give marks to whom can give the analytical proof.
更新1:
Definition: Let p > 1, define q by 1 / p + 1 / q = 1, then p and q are called " conjugate exponents". * It has good properties, e.g., (p - 1)(q - 1) = 1, but I am not asking the proof of this.