三角比,教下我(2)

2007-07-11 4:20 am
三角比,教下我(2)
化簡下列數式,教埋我,唔多識,長細d,唔好難,易明d唔該,教得好,私人+60分

因為打唔多個符號所以用○代替,度數=o

我想問其實點計架

求○的值
a)sin○=cos40o
b)tan○=cos0o(零o)
-------------------------------------------------------------------
求下列各題的值
a)sin60o
b)cos30ocos60o
c)sin90o
───
(cos)^2 60o

d)sin(90o-30o)cos(90o-30o)
更新1:

有冇msn,我想你教教我,得既話+多d分比你

回答 (2)

2007-07-11 4:29 am
✔ 最佳答案
a. sinθ = cos40°

sinθ = cos(90° - 50°)

sinθ = sin50°

θ = 50°


b. tanθ = cos0°

tanθ = 1

θ = 45°



a. sin60°

= √3/2

b. cos30°cos60°

= (√3/2)(1/2)

= √3/4

c. sin90°/cos²60°

= 1/(1/2)²

= 1/(1/4)

= 4

d. sin(90° - 30°)cos(90° - 30°)

= sin60°cos60°

= (√3/2)(1/2)

= √3/4

2007-07-10 20:30:21 補充:
求下列各題的值:呢啲係要記一記特別的度數,0度,30度,45度,60度,90度,配啲sin cos tan,會係咩數。記咗就會方便好多。或者可以用計算機~~~
參考: Myself~~~
2007-07-11 6:57 am
你冇講到θ的範圍......我只能給你一個通解.....你代所有的n也會得到正確的ans
a. sinθ = cos40°
sinθ = sin50°
θ = 180°n+50°[(-1)^n] n是整數
b. tanθ = cos0°
tanθ = 1
θ = 180°n+45° n是整數
a. sin60°
= √3/2
b. cos30°cos60°
= (√3/2)(1/2)
= √3/4
c. sin90°/cos²60°
= 1/(1/2)²
= 4
d. sin(90°-30°)cos(90°-30°)
= sin60°cos60°
= (√3/2)(1/2)
= √3/4
參考: 小心範圍的問題.......好多人也中了陷阱


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