By putting z=z+iy, find the complex number z which satisfies the equation
z+2z* = 15/2-i
where z* denotes the complex conjugate of z.
Thank you...
Complex no.
2007-07-10 12:01 am
回答 (1)
2007-07-10 12:21 am
✔ 最佳答案
z=x+iyz*=x-iy
z+2z* = 15/2-i
LHS=3x-iy
RHS=15(2+i)/[(2-i)(2+i)]=15(2+i)/(4+1)=6+3i
3x=6, x=2
-y=3, y=-3
z=2-3i
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