F.4 math

logk = 0.3

k = 2.0

Answer:

logk = 0.3

k = 10^0.3

k = 2.0

You may use your calculator to calculate this answer. Use, 0.3 shift log, then you may get the answer 1.995262315. This is the valvue of k.



2. R = h/2 + x²/6h

6R = 3h + x²/h

6Rh = 3h² + x²

3h² - 6Rh + x² = 0

h = {-(-6R) ± √[(-6R)² - 4(3)(x²)]}/2(3)

h = [6R ± √(36R² - 12x²)]/6

h = [3R ± √(9R² - 3x²)]/3




3. RT = (p + a²/v)(v - b)

RT = pv + a² - bp - a²b/v

RT + bp - a² = pv - a²b/v

(RT + bp - a²)v = pv² - a²b

pv² + (a² - bp - RT)v - a²b = 0

v = {-(a² - bp - RT) ± √[(a² - bp - RT)² - 4p(-a²b)]}/2p

v = {(RT + bp - a²) ± √[(a² - bp - RT)² + 4pa²b]}/2p



4. s = 1/2 gt² + ut

gt² + 2ut - 2s = 0

t = {-(2u) ± √[(2u)² - 4g(-2s)]}/2g

t = [-2u ± 2√(u² + 2gs)]/2g

t = [-u ± √(u² + 2gs)]/g