2+5i / -3+2i
*** i=radical (-1) ***
the correct ans should be 1/13(4-19i)
HOW TO calculate? >
complex no.! very urgent
2007-07-06 5:59 am
回答 (2)
2007-07-06 8:03 am
參考: me
2007-07-06 6:04 am
2 + 5i / -3 + 2i
= (2 + 5i)(-3 - 2i ) / (-3 + 2i )(-3 - 2i )
= (4 - 19i) / (9 + 4)
= (4 - 19i) / 13
= (2 + 5i)(-3 - 2i ) / (-3 + 2i )(-3 - 2i )
= (4 - 19i) / (9 + 4)
= (4 - 19i) / 13
收錄日期: 2021-04-13 00:43:57
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070705000051KK04708