F.2 maths..
回答 (6)
做呢d數要記住兩點:1)通分母 2)爆開佢(姐係約簡)
=(a-1)(a+2)-(a-2)(a+1)/(a+1)(a+2)
=a^2+a-2-a^2-a+2a+2/(a+1)(a+2)
=2a/(a+1)(a+2)
以後做呢類題目(分數)都離吾開以上兩點@@
吾識做可以試試(記住做分數要通同爆)
希望幫到你解決問題^^"
參考: 我既做數經驗-3-"
= [(a-1)(a+2) - (a-2)(a+1)] / (a+1)(a+2)
= (a^2 +a -2) - (a ^2 -a-2) / (a+1)(a+2)
= 2a / (a+1)(a+2)
OR 2a/(a^2 + 3a +2)
Simplify:
a-1 a-2
----- - ------
a+1 a+2
(a-1)(a+2) (a-2)(a+1)
---------------- - ----------------
(a+1)(a+2) (a+1)(a+2)
a + a + 2
--------------
(a+1)(a+2)
2a + 2
--------------
(a+1)(a+2)
2(a + 1)
--------------
(a+1)(a+2)
2
--------
a+2
(a-1)(a+2)-(a-2)(a+1)
=------------------------------
(a+1)(a+2)
a^2+a-2-a^2-a+2a+2
= -----------------------------
(a+1)(a+2)
2a/(a+1)(a+2)
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收錄日期: 2021-04-12 20:06:26
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