因式分解please!!
更新1:
+多1條...因式分解please!! 4x^2-4xy+y^2-2x+y =(2x-y)^2-2x+y
4x^2-4xy+y^2
回答 (3)
2007-07-04 2:08 am
✔ 最佳答案
1. 4x^2 - 4xy + y^2= (2x)^2 - 2 (2x) (y) + y^2
= (2x - y)^2
2. 4x^2 - 4xy + y^2 - 2x+y
= (2x - y)^2 - (2x - y)
= (2x - y) (2x - y - 1)
2007-07-03 7:17 pm
4x^2-4xy+y^2
=(2x)^2-2(2x)(y)+y^2
=(2x-y)^2
2007-07-03 11:19:30 補充：
4x^2-4xy+y^2-2x+y=(2x-y)^2-(2x-y)=(2x-y)(2x-y-1)
=(2x)^2-2(2x)(y)+y^2
=(2x-y)^2
2007-07-03 11:19:30 補充：
4x^2-4xy+y^2-2x+y=(2x-y)^2-(2x-y)=(2x-y)(2x-y-1)
2007-07-03 12:58 pm
4x^2-4xy+y^2
=(2x-y)(2x-y)
=(2x-y)^2
=(2x-y)(2x-y)
=(2x-y)^2
收錄日期: 2021-04-29 21:45:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070703000051KK00110