F4 amaths

👨🏻‍🏫 學術台數學

[匿名]

2007-06-26 4:07 am

Find the general solution of

(cosx)^2 = 1

in radiun measure.

更新1:

the answer is x = n(pi)

更新2:

oic! thx for Andy

回答 (2)

andycheungyatming

2007-06-26 4:27 am

✔ 最佳答案

cos² x = 1
cos x = ± 1
x = 2nπ or 2nπ ± π = mπ, m is an integer.

Do you know why? This is because 2n represents even integers, 2n ± 1 represents odd integers, they exhaust all the integers.

👍 0 👎 0

2007-06-26 4:35 am

cosx=1 or cosx=-1
x=360n or x=360n±180 (where n is an integer)

參考: my amath knowledge

👍 0 👎 0

收錄日期: 2021-04-27 12:05:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070625000051KK03985

檢視 Wayback Machine 備份