數學解難題

首先小明吃左十粒糖果,再把十張糖紙換曬佢=有五粒糖果,再吃左5粒糖果,又換曬佢=2粒糖果and1張糖紙,再吃左2粒糖果,換曬佢=2張糖紙同之前的1張糖紙=1粒糖果and1張糖紙.再吃左一粒糖果=2張糖紙,換曬佢=一粒糖果,再吃左一粒糖果=一張糖紙,再問人借1張糖紙,換曬佢=一粒糖果,再吃左一粒糖果,換左佢就剩番一張糖紙,再還番1張糖紙比人,咁小明就吃左二十粒糖果.

2007-06-28 00:54:14 補充：
我有看個etv所以我色.

10=10 (candy paper) 10/2=5 10+5=15 (candy) 15+(5/2)=17(candy) 17+1=18 (candy) 18+1=19 (eat candy) +2 (candy paper)

2007-06-29 16:08:49 補充：
and buy 1 candy (buy candy no paper)

1.小明吃了十粒糖果,剩下十張糖紙，可換(10/2)=5粒糖果! 他吃了:10粒糖果
2.小明吃了五粒糖果,剩下五張糖紙，可換(5/2)=2粒糖果和1粒糖紙 他吃了:(10+5)粒糖果
3.小明吃了二粒糖果,剩下二張糖紙，可換(2+1)/2=1粒糖果和1粒糖紙 他吃了:(10+5+2)粒糖果
4.小明吃了一粒糖果,剩下一張糖紙，不可換糖果了! Total他吃了:(10+5+2+1)=18粒糖果

5.但小明買多一粒, 便剩下二張糖紙,可換多一粒,即是 他吃了:(10+5+2+1+1+1)=20粒糖果

so,他要買多一粒糖果。

首先小明吃了十粒糖果,有十張糖紙,可換五粒,即吃了十五粒糖果,有五張糖紙,可換兩粒糖,餘下一張糖紙,買多兩粒,即吃了十九粒糖果,餘下三張糖紙,可換一粒,餘下一張糖紙。
小明要買多兩粒,才能吃到二十粒糖果。

Since siu ming got 10 warp papers, he could get 5 candies.
With 5 candies, he had 5 warp papers, he can get 2 candies and 1 warp paper.
With 2 candies, he had 2+1 warp papers, he can get 1 candy and 1 warp paper.
With 1 candy, he had 1+1 warp papers, he can get 1 candy.
With 1 candy, he had 1 warp paper, he can get 1 warp paper.
He had 10 candies and another 9 candies for free. He need to buy one candy more to have eaten 20 candies. Finally he had tasted 20 candies and 2 warp papers.