Trigonometic Functions

2007-06-22 9:11 pm
Why [(1+sinθ)/(1+cosθ)] * [(1+secθ)/(1+cosecθ)] = tanθ ?

回答 (1)

2007-06-22 9:38 pm
✔ 最佳答案
[(1+sinθ)/(1+cosθ)] * [(1+secθ)/(1+cosecθ)]
= [(1+sinθ)/(1+cosθ)] * [(1+1/cosθ)/(1+1/sinθ)]
= [(1+sinθ)/(1+cosθ)] * [((cosθ+1)/cosθ)/((sinθ+1)/sinθ)]
= [(1+sinθ)/(1+cosθ)] * [(cosθ+1)/(sinθ+1)] * sinθ/cosθ
= tanθ .................................after simplification


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https://hk.answers.yahoo.com/question/index?qid=20070622000051KK01483

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