Trigonometic Functions
回答 (1)
2007-06-22 9:38 pm
✔ 最佳答案
[(1+sinθ)/(1+cosθ)] * [(1+secθ)/(1+cosecθ)]= [(1+sinθ)/(1+cosθ)] * [(1+1/cosθ)/(1+1/sinθ)]
= [(1+sinθ)/(1+cosθ)] * [((cosθ+1)/cosθ)/((sinθ+1)/sinθ)]
= [(1+sinθ)/(1+cosθ)] * [(cosθ+1)/(sinθ+1)] * sinθ/cosθ
= tanθ .................................after simplification
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