Chemistry
2007-06-21 8:08 pm
A mixture od sodium chloride and soudium sulphate is known to contain 0.6 mole of chloride ion and 0.2 mole of sulphate ion. The number of mole of soudium ion present is?
回答 (2)
2007-06-21 8:24 pm
✔ 最佳答案
According to the stoichiometry of the two compounds:NaCl = 1 : 1
Na2SO4 = 2 : 1
So, no. of moles of sodium ions from sodium chloride = 0.6 moles
So, no. of moles of sodium ions from sodium shlphate = 0.2 × 2 = 0.4 moles
Therefore total no. of moles of sodium ion = 1 mole
參考: My chemical knowledge
2007-06-21 8:37 pm
sodium chloride (NaCl)
1 mole of NaCl contains 1 mole of Na+ and 1 mole of Cl-
Therefore, 0.6 mole of Cl- means there are 0.6 mole of NaCl and it contains 0.6 mole of Na+
sodium sulphate (Na2SO4)
1 mole of Na2SO4 contains 2 moles of Na+ and 1 mole of (SO4)2-
Therefore, 0.2 mole of (SO4)2- means there are 0.2 mole of Na2SO4 and which contains 0.4 mole of Na+
Therefore, there are totally 1 mole of Na+
1 mole of NaCl contains 1 mole of Na+ and 1 mole of Cl-
Therefore, 0.6 mole of Cl- means there are 0.6 mole of NaCl and it contains 0.6 mole of Na+
sodium sulphate (Na2SO4)
1 mole of Na2SO4 contains 2 moles of Na+ and 1 mole of (SO4)2-
Therefore, 0.2 mole of (SO4)2- means there are 0.2 mole of Na2SO4 and which contains 0.4 mole of Na+
Therefore, there are totally 1 mole of Na+
參考: Chemistry Knowledge
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