* = 次方
Please simplfiy the following expression,
1) (3 *2x)(27 *x+4) / 3 *2x-1
2) 13 *k+1 / 2 *2k 4 *k-2
Simple Indice
2007-06-20 11:54 pm
回答 (2)
2007-06-21 12:13 am
✔ 最佳答案
1)^ = 次方, * = 乘
(3^2x)(27^x+4) / 3^2x-1
= (3^2x)(3^3x+12) / 3^2x-1
= 3^ [(2x+3x+12)-(2x-1)]
= 3^3x+13
ie. 3 的 3x+13 次方
2)
13^(k+1)/ 2^2k * 4^(k-2)
= 13^(k+1)/ 2^2k * 2^(2k-4)
= 13^(k+1)/ 2^(2k+2k-4)
= 13^(k+1)/ 2^(4k-4)
= 13^(k+1)/ 16^(k-1)
呢條題目怪怪地, 都約唔到..
你 check 下係咪打錯野丫~
2007-06-21 12:15 am
1) [3*(2x) ][3*(3x+12)]/3*(2x-1)
=3*(2x+3x+12-2x+1)
=3*(3x+13)
2)13*k+1/{[2 *(2k)][2 *(2k-4)]}
=13*k+1/[2 *(2k+ 2k-4)]
=13*k+1/[2 *(4k-4)]
=13*k+1/[16 *(k-1)]
=3*(2x+3x+12-2x+1)
=3*(3x+13)
2)13*k+1/{[2 *(2k)][2 *(2k-4)]}
=13*k+1/[2 *(2k+ 2k-4)]
=13*k+1/[2 *(4k-4)]
=13*k+1/[16 *(k-1)]
收錄日期: 2021-04-23 22:06:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070620000051KK02496