✔ 最佳答案
If we divide the circle into many equal tiny sectors,
their shape will be approximately equal to the shape of many equal tiny isosceles triangles. i.e. :
. /\ . /\
/. \ approximate equal to /. \
/ \ . /_\
︶
sector isosceles triangles
If we put the triangles like this:
_ _
\ /\ \ /\
\. /. \ ........... \. /. \
. \/_\ \/_\
a parallelogram will form,
then the base of it is circumference/2=2 π r/2=π r, where r is the radius, π is "pi",
and its height approximately equal to radius=r
_ _
\ /\ \ /\
\. /. \ ........... \. /. \ r
. \/_\ \/_\
<---------- π r -------->
The area of the parallelogram =base x height=π r x r = π r²=The area of circle
So,The area of circle= π r²