得一題=[]=

3a) AQ = h / tan 20* m
BQ = h / tan30* m
= √3 h m

b) AQ + BQ = 134
h / tan 20* + √3 h = 134
h = 29.9 ( cor. to 3.s.f. )

(* The Q has a typing mistake, AB should be 134m. )

1a)tan20=PQ/AQ
AQ=PQ/tan20
tan30=PQ/BQ
BQ=PQ/tan30
=√3PQ

1b)AB=AQ+BQ
=√3PQ+PQ/tan20
=4.479528227PQ=134
PQ=29.91386441m