1+3+5+7+9.................84954645645124354569884653254325=?
回答 (4)
2007-06-19 2:49 am
✔ 最佳答案
= (1+84954645645124354569884653254325) / 2 x (1+84954645645124354569884653254325) / 2= [ (1+84954645645124354569884653254325) / 2 ] square
這樣大的數, 其實又有什麼意義呢 ?
2007-06-26 5:38 pm
Very true, who would be calculating a 33 digit number, without units without specific notations.... its rather pointless...
2007-06-19 6:30 am
the square of (1+84954645645124354569884653254325)/2=7217291816688646462862789675549..........6
參考: Olympiad Maths
2007-06-19 3:02 am
= (1+84954645645124354569884653254325) / 2 x (1+84954645645124354569884653254325) / 2
= [ (1+84954645645124354569884653254325) / 2 ]
= [ (1+84954645645124354569884653254325) / 2 ]
參考: me
收錄日期: 2021-04-13 00:38:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070618000051KK03379