✔ 最佳答案
1 D
(i) turning blue litmus paper to red is a property of acidic solutions
(ii)acidic solutions form carbon dioxide when mixed with carbonate ion containing compounds.
e.g. 2HCl+ Na2CO3 -------> H2O+CO2+NaCl
(iii) magnesium forms hydrogen gas when mixed with acidic solution
Mg+2H+ --------> H2+Mg2+
P.S. effervesces means gas bubbles
(iv) cathode is where cations gather during electrolysis. In a solution of acid, the only possible cations present are hydrogen ions. Hydrogen ions, being very ready to accept electrons and the only kind of cations present, receive electrons and form hydrogen gas.
2. no solution
Only the concentration of potassium hydroxide is given but not the volume(amount). Therefore, the 4 answers may be possible
3. A
(i) I don't know what you mean by blowing out all the liquids in a solution
so it may be possible, after considering the other points.
(ii) chlorine gas will be produced when bleaching solution is mixed with acidic solutions as they contain hydrogen ions.
Bleaching solutions contain hypochlorite ions (OCl-)
HOCl+HCl -------> H2O+Cl2
(iii) In molten calcium chloride, only calcium ions and chloride ions are present, therefore, calcium metal and chlorine gas are formed around the electrodes.
(iv) In brine solution, although the anions present include hydroxide ions and chloride ions, as the concentration of chloride ions is very high, chlorine will be produced around the anode.
4. D
(i) chlorine will oxidize sodium sulphite solution to sodium sulphate solution, BUT there is NO visible change as the two solutions are both COLORLESS
(ii) This method can only test for the presence of acidic gas. Chlorine will produce an acidic solution when mixed with water but hydrogen chloride gas have the same property when it is mixed with water as hydrochloric acid will be formed.
(iii) Chlorine will not react with potassium dichromate as the two solutions are both oxidizing agent.
(iv) potassium iodide will react with chlorine as chlorine will displace the iodide ions, forming potassium chloride. The solution will turn to dark when chlorine is present due to the formation of iodine
2007-06-19 18:16:24 補充:
Sorry, the answer should be 2A
2007-06-19 18:16:34 補充:
Sorry, I couldn't see "neutralize completely" in no. 2100cm3 of 1.2M H2SO4 (0.12 mol) requires 0.24 mol of KOHTherefore, 200cm3 of 1.2M KOH is needed2KOH H2SO4 --- K2SO4 2H2OTherefore, 0.12mol of salt is formedConcentration of salt solution=0.12/ [(100 200)/1000]M =0.4M