1.CO2(g),SO2(g) and O2(g) are composed of atoms of different elements.At room temperature and pressure,what is the ratio of the no of atoms involved in 100cm3 of CO2(g),100cm3 of SO2(g) and 200cm3 of O2(g)?(molar volume of gas at room temperature and pressure=24dm3)
A.3:4:4
B.3:4:2
C.2:3:4
D.1:1:2
Chem Question
2007-06-17 7:50 am
回答 (2)
2007-06-17 7:56 am
✔ 最佳答案
Since the three chemicals are all gases. So they occupy the same volume at room condition.For CO2 (g)
No. of mole of molecules
= 0.1/24
= 1/240 mol
No. of mole of atoms
= 1/240 X 3
= 1/80 mol
For SO2 (g)
No. of mole of molecules
= 0.1/24
= 1/240 mol
No. of mole of atoms
= 1/240 X 3
= 1/80 mol
For O2 (g)
No. of moles of molecules
= 0.2/24
= 1/120 mol
No. of mole of atoms
= 1/120 X 2
= 1/60 mol
Therefore, the required ratio is:
1/80 : 1/80 : 1/60
= 3 : 3 : 4
However, you don't have this choice in the question. Please check if you have typed the choice correctly~~~~
2007-06-17 10:56:37 補充：
Yes, maybe there are some mistakes in the original question. So, I have rechecked for many times, and I still get the answer 3:3:4. Also, the campanion below also calculated this answer. So maybe there's something wrong with the question.
參考: Myself~~~
2007-06-17 8:30 am
1C2O=3atoms
1S2O=3atoms
2(2O)=4atoms
as under RT&P
the no. of mole of gases are the same if they have same vol.
CO2:SO2:O2 = 3:3:4
1S2O=3atoms
2(2O)=4atoms
as under RT&P
the no. of mole of gases are the same if they have same vol.
CO2:SO2:O2 = 3:3:4
收錄日期: 2021-04-12 19:56:35
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