How to find the General Team of a Sequence?
(Show step)
1. 11/5,10/5,9/5,8/5
2. -4,-8,-12,-16
3. -3,-9,-27,-81
4. 1/2,1/4,1/8,1/16
S.1 Mathematics
2007-06-16 5:54 pm
回答 (2)
2007-06-16 6:13 pm
1. 11/5 x (10/5 / 11/5)(n-1)
=11/5 x 10/11(n-1)
2. -4+(n-1) x 4
=-4+4n-4
=4n-8
3. -3 x (-9/-3)(n-1)
=-3 x 3(n-1)
4. 1/2 x (1/4 / 1/2)(n-1)
=1/2 x 1/2(n-1)
唔知你睇唔睇得明！
=11/5 x 10/11(n-1)
2. -4+(n-1) x 4
=-4+4n-4
=4n-8
3. -3 x (-9/-3)(n-1)
=-3 x 3(n-1)
4. 1/2 x (1/4 / 1/2)(n-1)
=1/2 x 1/2(n-1)
唔知你睇唔睇得明！
參考: me
2007-06-16 6:06 pm
1. 11/5,10/5,9/5,8/5 = (12-n)/5
2. -4,-8,-12,-16 = -4n
3. -3,-9,-27,-81 = -3的n次方 (冇括號)
4. 1/2,1/4,1/8,1/16 = 1/2的n次方
希望可以幫到你!
2. -4,-8,-12,-16 = -4n
3. -3,-9,-27,-81 = -3的n次方 (冇括號)
4. 1/2,1/4,1/8,1/16 = 1/2的n次方
希望可以幫到你!
參考: 自己
收錄日期: 2021-04-12 19:56:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070616000051KK00885