✔ 最佳答案
x+y=m+2 4x+5y=6m+3
4x+5y=6m+3
4x+4y+y = 6m+3
4(x+y)+y = 6m+3
4(m+2)+y = 6m+3
4m+8+y = 6m+3
y = 2m-5
m = (y+5)/2
Here, m = 3 is smallest when y = 1, so m>=3
x+y=m+2
y = m+2-x
From above, 4(m+2)+y = 6m+3
4(m+2)+m+2-x = 6m+3
x = 7-m
m = 7-x
Here, m = 6 is largest when x = 1, so m<=6
Combine the two ranges, 3=<=6.
2007-06-14 12:11:44 補充:
3 =
2007-06-14 12:12:46 補充:
Don't why can't show ar,Anyway, the answer is "3 less than or equal to m less than or equal to 6".
2007-06-14 14:10:24 補充:
Thanks T#, I thought x and y are positive integers.So T#'s answer is closer, but I am just not sure that whether 0 is positive.I guess it's neither positive nor negative.If x and y can't equal 0, then final answer will be: 2.5 < m < 7