解一題簡單不等式~~急......
2007-06-14 12:47 am
回答 (2)
2007-06-14 2:11 am
✔ 最佳答案
-1≤(2y-5)/(y+1)≤1-1≤(2y-5)/(y+1)
-y-1≤2y-5
4≤3y
4/3≤y
(2y-5)/(y+1)≤1
2y-5≤y+1
y≤6
∴4/3≤y≤6
參考: Me
2007-06-14 3:42 am
-1≤(2y-5)/(y+1)≤1
-1≤(2y-5)/(y+1)
-1(y+1)≤(2y-5)
-y-1+5≤2y
-y+4≤2y
4≤3y
4/3≤y
(2y-5)/(y+1)≤1
(2y-5)≤(y+1)
y≤6
4/3≤y≤6
-1≤(2y-5)/(y+1)
-1(y+1)≤(2y-5)
-y-1+5≤2y
-y+4≤2y
4≤3y
4/3≤y
(2y-5)/(y+1)≤1
(2y-5)≤(y+1)
y≤6
4/3≤y≤6
收錄日期: 2021-04-23 21:24:54
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070613000051KK02639