Solve the equation.
100y = 4100000 - 300(2y+150)
maths (f.1)
2007-06-13 11:09 pm
回答 (4)
2007-06-13 11:15 pm
✔ 最佳答案
100y = 4,100,000 - 300(2y+150)100y = 4,100,000 - 600y - 45,000
700y = 4,100,000 - 45,000
700y = 4,055,000
y = 5792.86 (to 2 d.p)
2007-06-15 9:25 pm
100y=4100000 - 300(2y+150)
100y=4100000 - 300(2y+150)
100y=4100000 - 600y - 45000
100y+600y=4100000 - 45000
700y=4055000
y=4055000/700
y=5792.857(correct to 3 decimal place)
100y=4100000 - 300(2y+150)
100y=4100000 - 600y - 45000
100y+600y=4100000 - 45000
700y=4055000
y=4055000/700
y=5792.857(correct to 3 decimal place)
2007-06-13 11:40 pm
100y = 100 (41000 - 3 (2y+150))
y = 41000 -6y -450
7y = 40550
y = 5792.86 (corr. to 2d.p.)
y = 41000 -6y -450
7y = 40550
y = 5792.86 (corr. to 2d.p.)
參考: ME
2007-06-13 11:27 pm
100y = 4100000 - 300(2y+150)
100y = 4100000 - 600y - 45000
100y +600y = 4100000 - 45000
700y = 4055000
y=5792.8571
100y = 4100000 - 600y - 45000
100y +600y = 4100000 - 45000
700y = 4055000
y=5792.8571
收錄日期: 2021-04-13 00:56:36
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