Form2 IS Electricity (with a circuit picture)

2007-06-13 4:00 am
This is a parallel circuit.
_______|l|l_________
◎-A1...................... ◎-A4
|___◎-A3__∩__∩__|
|_____◎-A2____∩__|

Key:
∩=Light bulb
◎=Ammeter
| or ______ = wires
.................=Just ignore it不用理會
問題:
Assume all the light bulbs are identical and the reading of ammeter A3 is 0.75A and A4 is 2.25A. Find the missing ammeter readings of A1 and A2. Show your steps of calculation.
A1= ___?___A
A2= ___?___A
(請用中文explain why)

回答 (2)

2007-06-13 4:24 am
✔ 最佳答案

圖片參考:http://hk.geocities.com/namsm4e/P0269.jpg

A1 是和 A4 是串聯一起所以電流相同
A1 = 2.25A
A1 分成兩分支,其中一分支的電流是 0.75A
則其他的電流便會流至另一分支
I = 2.25 – 0.75 = 1.5A
所以 A2 的電流是 1.5A
答案
A1 = 2.25A
A2 = 1.5A
2007-06-13 4:04 am
A1=A2+A3=1.5 A4=2.25


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