Factorize
r^2 + 10r + 25 - s^2
急問!唔該! 中三factorization一題
2007-06-11 10:24 pm
回答 (3)
2007-06-11 10:42 pm
= r^2 + 2*5*r + 5^2 -s^2
= (r+5)^2 - s^2
= (r+5+s) (r+5-s)
as (A+B)(A-B) = A^2 - B^2
= (r+5)^2 - s^2
= (r+5+s) (r+5-s)
as (A+B)(A-B) = A^2 - B^2
2007-06-11 10:31 pm
r^2 + 10r + 25 - s^2
= r^2 + 2*5*r + 5^2 -s^2
= (r+5)^2 - s^2
= (r+5+s) (r+5-s)
as (A+B)(A-B) = A^2 - B^2
= r^2 + 2*5*r + 5^2 -s^2
= (r+5)^2 - s^2
= (r+5+s) (r+5-s)
as (A+B)(A-B) = A^2 - B^2
收錄日期: 2021-04-13 00:36:51
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070611000051KK01826