一條....解方程
x^2+2x=a^2+2a
數學!!!解方程!!!
2007-06-11 1:57 am
回答 (3)
2007-06-11 2:14 am
✔ 最佳答案
........x² + 2x = a² +2a..........x² - a² = 2a -2x
(x + a)(x - a) = 2(a - x)
(x + a)(x - a) = -2(x - a)
...........x + a = -2
參考: 唔知啱唔啱....
2007-06-11 2:07 am
數學D題目成日都吾好好Define d 符號:(
Anyway, a系math黎講9成9系constant,
所以可以當普通數做.
x^2+2x-a^2-2a=0
x={-2±√[2^2-4(1)(-a^2-2a)]}/2
x=[-2±√(4a^2+8a+4)]/2
x=(a-1)/2
or
x=(-a-3)/2
Anyway, a系math黎講9成9系constant,
所以可以當普通數做.
x^2+2x-a^2-2a=0
x={-2±√[2^2-4(1)(-a^2-2a)]}/2
x=[-2±√(4a^2+8a+4)]/2
x=(a-1)/2
or
x=(-a-3)/2
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https://hk.answers.yahoo.com/question/index?qid=20070610000051KK03743