詳細一些好嗎 ?
ax-bx-ay+by+az-bz
更新1:
=x(a-b)-y(a-b)+z(a-b) =(x-y+z)(a-b) 但係點解係y(a-b) 唔係y(a+b) 嘅 !?
怎樣計算下列問題 ?
回答 (4)
2007-06-10 2:34 am
✔ 最佳答案
條數問乜架先?? factorize嗎? 正路計ge.. 應該係抽x, y, z 出黎
即係....
= x(a-b) - y(a-b) - z(a-b)
= (x-y-z) (a-b)
參考: me
2007-06-17 1:59 am
ax-bx-ay+by+az-bz
=x(a-b)-y(a-b)+z(a-b)
=(x-y+z)(a-b)
...因為佢係抽出咗(-y),所以由(-ay+by),變為-y(a-b)。
因為佢為咗最後可以抽出(a-b),所以佢係抽出咗(-y)。
=x(a-b)-y(a-b)+z(a-b)
=(x-y+z)(a-b)
...因為佢係抽出咗(-y),所以由(-ay+by),變為-y(a-b)。
因為佢為咗最後可以抽出(a-b),所以佢係抽出咗(-y)。
參考: me ...............係咪好聰明呢!!^^
2007-06-10 3:15 am
I know what you mean .Is it like the following ?
ax-bx-ay+by+az-bz = a(x-y+z)+b(-x+y-z)
= a(x-y+z)+(-b)(x-y+z)
= (a+(-b))(x-y+z)
= (a-b)(x-y+z)
ax-bx-ay+by+az-bz = a(x-y+z)+b(-x+y-z)
= a(x-y+z)+(-b)(x-y+z)
= (a+(-b))(x-y+z)
= (a-b)(x-y+z)
2007-06-10 2:34 am
x(a-b)-y(a-b)+z(a-b)
=(x-y+z)(a-b)
=(x-y+z)(a-b)
收錄日期: 2021-04-20 23:34:03
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https://hk.answers.yahoo.com/question/index?qid=20070609000051KK03687