e 條數係要搵邊d 係similar triangle..
但係我唔知點寫式...
有冇人可以教下我點prove 呀?
我條問題upload 左去條link 到...
link: http://www1.filehost.to/files/2007-06-08_02/100753_Maths_15.bmp
thx~
1 條Form 2 數.. 入黎啦``
2007-06-09 12:10 am
回答 (6)
2007-06-09 12:21 am
✔ 最佳答案
答案係A,所以如果要証明triangleABD~triangleACB首先
因為 angle ABD = angle ACB
angle BAC = angle CAB
咁睇triangleABD 同triangleACB
三角形內角有兩隻相同,第三隻一定係相同啦
So, angle ADB = angle ABC
因此兩個三角形內角三隻一樣就一定係相似三角形啦
所以triangleABD~triangleACB
2007-06-22 9:35 am
angle ABD=angle ACB (given)
angle BAC=angle BAD(same)
so angle ADB=angle ABC( sum of triangle)
so they are similar(A.A.A)
angle BAC=angle BAD(same)
so angle ADB=angle ABC( sum of triangle)
so they are similar(A.A.A)
2007-06-09 12:25 am
In triangle ABD & triangle ACB,
2007-06-13 19:40:40 補充：
用AAA但係只証2個以可以(
2007-06-13 19:40:40 補充：
用AAA但係只証2個以可以(
參考: me
2007-06-09 12:17 am
Because Angle ABD =Angle DCB
SO it is similar.
SO it is similar.
2007-06-09 12:15 am
對不起，太難了！
收錄日期: 2021-04-12 19:54:14
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070608000051KK02141