請幫我解開以下一條數

2007-06-07 4:56 am
請幫我解開以下一條數
15 = p + 0.25 p

回答 (8)

2007-06-08 12:01 am
15 = p (1+0.25)
15 = p (1.25)
15/1.25=p
p= 12
2007-06-07 5:16 am
15=p+0.25p
15-0.25=p+0.25p-0.25
14.75=p+0.25(p-1)
14.75-0.25=p+0.25(p-1)-0.25
14.5=p+0.25(p-2)...
13=p+0.25(p-6)...
12.5=p=0.25(p-8)
p=10
2007-06-07 5:10 am
0.25x12=3 12+3=15 p=15
2007-06-07 5:07 am
15 =0.26p
15/0.26 =0.26p/0.26
57.6923077=p
2007-06-07 5:02 am
15 = 1.25p
p = 15/1.25
p = 12
2007-06-07 5:02 am
15 = p + 0.25 p
15=1.25p
p=15/1.25
p=12
2007-06-07 5:01 am
我識~
15=p+0.25p
15=1.25p
15被1.25除=p
12=p

2007-06-06 21:03:40 補充:
可能你唔明架原因:p前面係有1的因為一個數就算係無講x幾p=1xp=p所以,0.25p+p可以睇成0.25p再1p,加減變化不用多說吧~~除變乘,加變減所以左邊變左15被1.25除答案就係咁簡單^^~希望幫倒你~~
參考: 自己架數學成績
2007-06-07 5:01 am
15=p+0.25p
15=1.25p
p=12

希望幫到你!!^^
參考: me


收錄日期: 2021-05-03 17:36:52
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070606000051KK04245

檢視 Wayback Machine 備份