silmplify
~~~~~~ use to fill the space , hope you understand
~~~10~~~~~~~~~2~~~~~~
----------------- - -------------------
( x^2 + x - 6 )~~~~( x - 2 )~~
maths ce level
2007-06-07 3:54 am
回答 (2)
2007-06-07 4:02 am
✔ 最佳答案
10 / (x^2 + x - 6) - 2 / (x - 2)= 10 / [ (x + 3)(x - 2) ] - 2 / (x - 2)
= 10 / [ (x + 3)(x - 2) ] - 2 (x + 3) / [ (x + 3)(x - 2) ]
= [ 10 - 2 (x + 3) ] / [ (x + 3)(x - 2) ]
= -2(x - 2) / [ (x + 3)(x - 2) ]
= -2 / (x + 3)
2007-06-07 4:03 am
先 factorize (x^2+x-6) 做 (x-2)(x+3)
=10 / (x-2)(x+3) - 2 / (x-2)
抽 factor
=[ 2/(x-2) ] [ 5/(x+3) - 1 ]
=[ 2/(x-2) ] [ -x+2/(x+3) ]
= -2 /(x+3)
=10 / (x-2)(x+3) - 2 / (x-2)
抽 factor
=[ 2/(x-2) ] [ 5/(x+3) - 1 ]
=[ 2/(x-2) ] [ -x+2/(x+3) ]
= -2 /(x+3)
參考: 自己
收錄日期: 2021-04-13 15:17:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070606000051KK03832