搵代數=幾多
1. 2(b+2)/3 - 3/4 = 2b+1/4
2. 3-[5x-(2x-3)] = x-16
3. -2[5(3-x)+3]-1 = 3[2(3-x)+3]
***要有步驟***
收錄日期: 2021-04-13 00:35:05
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070605000051KK02754