以下有3條不太懂寫證明,麻煩幫幫助,謝謝^^"
1.C是BD的中點,且AB=BC,求證3AB>AD
http://i54.photobucket.com/albums/g111/Tim-Mx/S6000239.jpg
2.AOB是直線,以x表示y
http://i54.photobucket.com/albums/g111/Tim-Mx/S6000240.jpg
3.CDE,CBA,DFA,BFE是直線,BC=AC和a1=a2,
求證三角形ADC全等於三角形EBC
http://i54.photobucket.com/albums/g111/Tim-Mx/S6000242.jpg
演繹幾何查詢
2007-06-04 3:21 am
回答 (1)
2007-06-04 8:42 am
✔ 最佳答案
2)3x - 70 + y = 180
y = 250 - 3x
3)
角 ECB = 角 ACD (common angle)
CD = CB (given)
角 ADC = 180 - a1 = 180 - a2 = 角 EBC
by A.S.A, 三角形 ADC 全等於三角形 EBC
1)
3AB
= AB + BC + CD (given)
= AB + BD
> AD
三角形特性, 兩條邊相加一定大過剩返果條
唔算好難,用心諗下應該諗到
收錄日期: 2021-04-23 17:01:11
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070603000051KK04168