how to solve (2a+3b)(4a+5b)
回答 (2)
2007-06-03 4:22 pm
✔ 最佳答案
(2a+3b)(4a+5b)=8a2<-(square)+10ab+12ab+15b2<-(square)
=8a2<-(square)+22ab+15b2<-(square)
首先要拆( )括號, 然後將2a和4a,2a和5b乘埋佢..因為拆咗括號,再將3b和4a,3b和5b乘埋佢禁咪變咗做 8a2+10ab+12ab+15b2 lo!!!!
2007-06-03 4:17 pm
(2a+3b) x (4a+5b)
=2a x 4a + 3b x 5b ------ *** Similar to 2(a+b) is also equal to 2a+2b
=8a+15b
So the final answer should be 8a+15b.
=2a x 4a + 3b x 5b ------ *** Similar to 2(a+b) is also equal to 2a+2b
=8a+15b
So the final answer should be 8a+15b.
收錄日期: 2021-04-23 22:03:37
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070603000051KK00733