the equation of a curve is given by X= 3t/ (1+t^3) and y= (3t^2) /(1+t^3) where t is parameter
1, show that (3/2,3/2) is a point on the curve and find the value of t corresponding to this pt.
2, show that the equation of the curve can be represented by X^3+y^3=3xy
amaths
2007-06-03 8:04 am
回答 (1)
2007-06-03 8:16 am
✔ 最佳答案
1)t = 1
put t = 1 into x = 3t/ (1+t^3) and y = (3t^2) /(1+t^3)
x = 3/2 and y = 3/2
so, completed
2)
y/x = t ------- (1)
put (1) into x = 3t/ (1+t^3)
and simply and rearrange,
you can get the answer
收錄日期: 2021-04-12 20:37:36
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070603000051KK00025