A-amths!!!!

2007-06-03 6:18 am
Give that coseA+cotA=3,evaluate cosecA-cotA and cosA

回答 (1)

2007-06-03 7:08 am
✔ 最佳答案
(2)
cscA+cotA=3
(1/sinA)+(cosA/sinA) =3
1+cosA=3sinA
(1+cosA)²=9sin²A
1+cos²A+2cosA=9-9cos²A
10cos²A+2cosA-8=0
(5cosA-4)(cosA+1)=0
cosA=4/5 or -1(rejected)

-------------------- --------------------
(1)
cscA-cotA
=(1/sinA)-(cosA/sinA )
=(1-cosA)/sinA
=(1+cosA)/[(1+cosA)/3]
=3(1+cosA)/(1+cosA)
=3(1+4/5)/(1+4/5)
=3


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