physics !

2007-06-02 11:07 pm
Some ice cubes (0.1kg, 0 deg.C) are added to a glass of Coke (0.3kg, 25deg.C).If no heat is lost to the surroundings, find thetemperature T of he misture . Is T higher or lower in reality,why ?

Please do it step by step , thank you =]

回答 (1)

2007-06-03 4:37 am
✔ 最佳答案
We use the following figures:
Specific latent heat of fusion of ice = 3.34 × 105 J/kg
Specific heat capacity of coke (water) = 4200 J/kg K
So suppose that there's no heat exchange with the surroundings.
Then,
Heat gain of ice = 0.1 × 3.34 × 105 = 33400 J (when ice melts to 0°C water)
Heat loss of coke = 0.3 × 4200 × 25 = 31500 J (when cool down to 0°C coke)
So to speak, the final temperature will be 0°C with the resulting mixture of ice and coke + water.
In reality, the temperature will be higher since there's a heat gain to the coke + ice as the surrounding temperature is higher than that of the coke.
參考: My physics knowledge


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