幾何題(已知:三角形abc,角A:角B:角C=2:3:5,求角A,角B,角C的度數)
回答 (1)
2007-06-01 3:32 am
✔ 最佳答案
Let 角A:角B:角C=2:3:5 = 2c : 3c : 5c (c > 0)2c + 3c + 5c = 180
10c = 180
c = 18
A : 2c = 36
B : 3c = 54
C : 5c = 90
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