小六方程***

媽媽原有 x 元
(x - 32) * 2/3 = 64
x - 32 = 96
x = 128

設媽媽原有a元.
(a - 32) ×(1 -1 / 3) = 64
(a - 32) ×(2 / 3) = 64
a - 32 = 64 ÷ 2/3
a - 32 = 64 × 3/2
a - 32 = 96
a = 96 + 32
a = 128
媽媽原有128元.

設原有x元
(x-32)(1-1/3)=64
2/3(x-32)=64
x-32=64x3/2
x=96+32
x=128

設媽媽原有y元.
(y - 32) ×(3 -1 / 3) = 64
(y - 32) ×(2 / 3) = 64
y - 32 = 64 ÷ 2/3
y - 32 = 64 × 3/2
y - 32 = 96
y = 96 + 32
y = 128
媽媽原有128元.

設原有 $X

X - 32 - (X-32) x 1/3 = 64

2X = 256

X = 128

原有 $128

媽媽原有A元
( A-32 )ｘ2/3 = 64
( A-32 )ｘ2/3 ÷ 1/3 =64÷2/3
( A-32 )=96
A-32+32 =96+32
A=128
媽媽原有128元

設原有x元
x - [ (x-32) over 3 ] = 64

Let $x be the money that mother have originally.
1-1/3(x-32)=64
2/3(x-32)=64
x-32=96
x=128
Mother have $132 originally.

2007-05-28 19:40:03 補充：
Sorry!!Mother have $132 originally(Wrong answer)It should be--Mother have $128 orginally.

2007-05-28 19:41:38 補充：
wl01751633You give wrong answer--餘款&還有It should be 1-2/3

未買了兩條魚之前,媽媽有64/(2/3)=$96
96+32=$128