MaThS
2007-05-24 4:34 am
There is a square with each side 12cm. If the length is increased by x cm ,the width is decreased by x cm. the length will be twice of the width. Find the area of the new rectangle.
回答 (3)
2007-05-24 4:41 am
✔ 最佳答案
first need to find out the value of x,(12+x)=2(12-x)
12+x=24-2x
x=4
therefore, the new square, length=12+4=16, width=12-4=8
area=16*8=128
2007-05-24 4:45 am
i don't know is it correct or not,
i just try
the width:
(12+x)÷(12-x)=2
the length:
2×width
the area:
length×width
you try it la~
hope can help you
i just try
the width:
(12+x)÷(12-x)=2
the length:
2×width
the area:
length×width
you try it la~
hope can help you
參考: me
2007-05-24 4:44 am
new length = (12+x)cm
new width = (12-x) cm
since length will be twice of the width
12+x = 2 ( 12 - x)
x = 4
area of the new rectangle = (12+4) X ( 12 - 4)
= 128 cm square
new width = (12-x) cm
since length will be twice of the width
12+x = 2 ( 12 - x)
x = 4
area of the new rectangle = (12+4) X ( 12 - 4)
= 128 cm square
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