help a.maths~~~

As follows:

圖片參考：http://i117.photobucket.com/albums/o61/billy_hywung/May07/Crazydiff29.jpg


圖片參考：http://i117.photobucket.com/albums/o61/billy_hywung/May07/Crazydiff30.jpg

1.dy/dx=3(2x+1)^2(2)(3x-2)^4+(2x+1)^3*4(3x-2)^3(3)
=6(2x+1)^2(3x-2)^4+(2x+1)^3*12(3x-2)^3
=(2x+1)^2(3x-2)^3[6(3x-2)+12(2x+1)]
=(2x+1)^2(3x-2)^3(18x-12+24x+12)
=42x(2x+1)^2(3x-2)^3

2.dy/dx=(x^2+3)^2[3(2x-1)^2(2)]+(2x-1)^3[2(x^2+3)(2x)]
=(x^2+3)^2[6(2x-1)^2]+(2x-1)^3[4x(x^2+3)]
=(x^2+3)(2x-1)^2[6(x^2+3)+4x(2x-1)]
=(x^2+3)(2x-1)^2[6x^2+18+8x^2-4x]
=2(x^2+3)(2x-1)^2(7x^2-2x+9)

3.dy/dx=4(3x-2)/(x+3)^3(x+3)(3)-(3x-2)(1)/(x+3)^2
=4(3x+9-3x+2)(3x-2)^3/(x+3)^5
=44(3x-2)^3/(x+3)^5

4.dy/dx=(2x-1)^2[4(2x+3)^3)(2)]-(2x+3)^4[2(2x-1)(2)]/(2x-1)^4
=(2x-1)^2[8(2x+3)^3]-(2x+3)^4[4(2x-1)]/(2x-1)^4
=(2x+3)^3(2x-1)[8(2x-1)-4(2x+3)]/(2x-1)^4
=(2x+3)^3[16x-8-8x-12]/(2x-1)^3
=(2x+3)^3(8x-20)/(2x-1)^3
=4(2x+3)^3(2x-5)/(2x-1)^3

1.dy/dx=6(2x+1)^2(3x-2)^4+12(2x+1)^3(3x-2)^3
2.dy/dx=4x(x^2+3)(2x-1)^3+6(x^2+3)^2(2x-1)^2
3.dy/dx=28[(3x-2)^3]/(x+3)^5
4.dydx=[8(2x+3)^3(2x-1) - 2(2x+3)^4]/(2x-1)

1)
(2)(3) (2x+1)^2 (3x-2)^4 + (2x+1)^3 (3)(4) (3x-2)^3
=(2)(3) (2x+1)^2 (3x-2)^3 (3x - 2 + 4x + 2)
= 42x (2x+1)^2 (3x-2)^3

其他大同小異,自己慢慢試下做