數學問題..

1. 3份之x + 2有2份之1 = 4
x/3+2(1/2)=4
x/3=(8/2)-(5/2)
x=3(3/2)
x=9/2

2. 8份之3y - 2 = 10
[(3y)/8]-2=10
(3y)/8=10+2
3y=12(8)
y=96/3
y=32

3. 0.6z - 1.7 = 4.3
0.6z=4.3+1.7
z=6/0.6
z=10

4. 3份之2s + 1 有2份之1 = 9有2份之1
[(2s)/3]+1(1/2)=9(1/2)
[(2s)/3]+3/2=19/2
[(2s)/3]=19/2-3/2
(2s)=(16/2)*3
s=(48/2)*2
s=48


5. a + 5 = 11
a+5=11
a=11-5
a=6

6. b - 7 = 6
b-7=6
b=6+7
b=13

7.3c = 21
c=21/3
c=7

8. 5份之d = 4
d/5=4
d=4*5
d=20

9. 8份之a = 9
a/8=9
a=9*8
a=72

10. 6份之5d = 15
(5d)/6=15
5d=15*6
d=90/5
d=18

11. k x 45% = 135
k*45%=135
k=135/45%
k=300

x / 3 + 5 / 2 =4
x = 3 / 4 乘 3
x = 9 / 4

3y / 8 - 2 = 10
3y = 96
y = 32

0.6z - 1.7 = 4.3
z = 6 / 0.6
z = 10

2s / 3 + 3 / 2 = 19 / 2
s = 8 x 3 / 2
s = 12

a + 5 = 11
a = 6

b - 7 = 6
b = 13

3c = 21
c = 7

d / 5 = 4
d = 20

a / 8 = 9
a = 72

5d / 6 = 15
d = 18

0.45k = 135
k = 300

2007-05-15 17:34:58 補充：
第一題打錯．．．＠＠x / 3 5 / 2 =4 x = 3 / 2 乘 3x = 9 / 2

1. 3份之x + 2有2份之1 = 4
x/3=4-5/2
x/3=3/2
x=4有2份之1

2. 8份之3y - 2 = 10
3y/8=10+2
3y=12x8
y=32

3. 0.6z - 1.7 = 4.3
0.6z=4.3+1.7
z=6/0.6
z=10

4. 3份之2s + 1 有2份之1 = 9有2份之1
2s/3+3/2=19/2
2s/3=19/2-3/2
2s/3=16/2
s=12

5. a + 5 = 11
a=11-5
a=6

6. b - 7 = 6
b=6+7
b=13

7.3c = 21
c=21/3
c=7

8. 5份之d = 4
d/5=4
d=4x5
d=20

9. 8份之a = 9
a/8=9
a=8x9
a=72

10. 6份之5d = 15
5d/6=15
5d=15x6
d=90/5
d=18

11. k x 45% = 135
k=135x100/45
k=300

1. x =2份之9
2.y=32
3.z=10
4.s=12
5.a=6
6.b=13
7.c=7
8.d=20
9.a=72
10.d=18
11.k=300

1. x/3+2又1/2=4
x/3=1+1/2
x=4又2份1

2. 3y/8-2=10
3y/8=12
y=32

3. 0.6z-1.7=4.3
0.6z=6
z=10

4. 2s/3+1又1/2=9又1/2
2s/3=
s=12

5. a+5=11
a=11-5
=6

6. b-7=6
b=6+7
=13

7. 3c=21
c=21/3
=7

8. d/5=4
d=4乘5
=20

9. a/8=9
a=9乘8
=72

10. 5d/6= 15
d=15乘6/5
=18

11. k乘45%=135
k=135/45/100
=300

3份之x + 2有2份之1 = 4
x/3+2(1/2)=4
x/3=(8/2)-(5/2)
x=3(3/2)
x=9/2

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