(x-1)(x+3)=12
算式+答案
(x-1)(x+3)=12
2007-05-15 12:47 am
回答 (7)
2007-05-15 12:51 am
✔ 最佳答案
(x-1)(x+3)=12 x²+2x-3=12
x²+2x-15=0
(x-3)(x+5)=0
x=3 or -5
參考: By CY
2007-05-18 2:55 am
(x-1)(x+3)=12
x^2 -x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x=3
x^2 -x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x=3
2007-05-15 1:13 am
x²+2x-3=12
x²+2x-15=0
(x-3)(x+5)=0
x=3 or -5
x²+2x-15=0
(x-3)(x+5)=0
x=3 or -5
2007-05-15 12:55 am
(x-1)(x+3)=12
x^2-x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x-3=0 or x+5=0
x=3 or x= -5
Ans:x等於3或-5。
x^2-x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x-3=0 or x+5=0
x=3 or x= -5
Ans:x等於3或-5。
2007-05-15 12:53 am
(x-1)(x+3)=12
x^2 -x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x=3 or
= -5
x^2 -x+3x-3=12
x^2+2x-15=0
(x-3)(x+5)=0
x=3 or
= -5
收錄日期: 2021-04-18 22:12:16
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070514000051KK02414