differentiate the functions with respect to x.
y=(x+5)(2x-1)^2*(x+1)^3
Ans:4(x+1)^2*(2x-1)(3x^2+13x+1)
A.Maths
2007-05-14 7:15 am
回答 (2)
2007-05-14 7:43 am
參考: My Maths knowledge
2007-05-14 7:38 am
y = (x + 5)(2x - 1)2‧(x + 1)3
dy/dx = (2x - 1)2(x + 1)3 + 4(2x - 1)(x + 5)(x + 1)3 + 3(x + 1)2(x + 5)(2x - 1)2
dy/dx = (2x - 1)(x + 1)2[(2x – 1)(x + 1) + 4(x + 5)(x + 1) + 3(x + 5)(2x - 1)]
dy/dx = (2x - 1)(x + 1)2(2x2 + x – 1 + 4x2 + 24x +20 + 6x2 + 27x - 15)
dy/dx = (2x - 1)(x + 1)2(12x2 + 52x + 4)
dy/dx = 4(x + 1)2(2x - 1)(3x2 + 13x + 1)
dy/dx = (2x - 1)2(x + 1)3 + 4(2x - 1)(x + 5)(x + 1)3 + 3(x + 1)2(x + 5)(2x - 1)2
dy/dx = (2x - 1)(x + 1)2[(2x – 1)(x + 1) + 4(x + 5)(x + 1) + 3(x + 5)(2x - 1)]
dy/dx = (2x - 1)(x + 1)2(2x2 + x – 1 + 4x2 + 24x +20 + 6x2 + 27x - 15)
dy/dx = (2x - 1)(x + 1)2(12x2 + 52x + 4)
dy/dx = 4(x + 1)2(2x - 1)(3x2 + 13x + 1)
收錄日期: 2021-05-03 06:51:56
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070513000051KK05645