4/5x-(-x+5)= -(x-3)-2/5(2+2x)

2007-05-13 8:01 am
好困難ge方程式!!!!!help下我!!thx
仲有就係我要條算式+!!5好just俾個答案我.
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回答 (2)

2007-05-13 8:11 am
✔ 最佳答案
首先, 令全部變成整數, 成條式乘5
4x - 5(-x+5) = -5(x-3) - 2(2+2x)

跟住拆括號
4x + 5x - 25 = -5x + 15 - 4 - 4x
4x + 5x + 5x + 4x = 15 - 4 + 25
18x = 36
x = 2
2007-05-13 8:21 am
4/5x-(-x+5)= -(x-3)-2/5(2+2x)

4/5x+x-5= -x+3-4/5-4/5x

4/5x+8/5x+x-5= -x+3

12/5x = -x+3-x+5

12/5x = -2x+8

12/5x = -2x+8

2-2/5x +2x = 8

4-2/5x = 8


22/5x/2 = 8 /2

11/5x = 4

11 = 4(5x)

11 = 20x

11/20 = x


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