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設直線kx+3y-7=0與直線3x+2y-5=0互相垂直，則k=??
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求直線未知數....
2007-05-12 10:15 pm
回答 (2)
2007-05-12 10:23 pm
✔ 最佳答案
L1 be the straight line equation of kx+3y-7=0L2 be the straight line equation of 3x+2y-5=0
the slope of L1 = - k/3
the slope of L2 = -3/2
L1 is perpendicular to L2
therefore,
(the slope of L1 )(the slope of L2)=-1
(- k/3)(-3/2)=-1
k=-2
2007-05-12 10:39 pm
L1 be the straight line equation of kx+3y-7=0
L2 be the straight line equation of 3x+2y-5=0
the slope of L1 = - k/3
the slope of L2 = -3/2
L1 is perpendicular to L2
therefore,
(the slope of L1 )(the slope of L2)=-1
(- k/3)(-3/2)=-1
k=-2
L2 be the straight line equation of 3x+2y-5=0
the slope of L1 = - k/3
the slope of L2 = -3/2
L1 is perpendicular to L2
therefore,
(the slope of L1 )(the slope of L2)=-1
(- k/3)(-3/2)=-1
k=-2
參考: 我姐姐
收錄日期: 2021-04-25 17:19:06
原文連結 [永久失效]:
https://hk.answers.yahoo.com/question/index?qid=20070512000051KK02451