differentiate the functions with respect to x.
y=(2x+3)^4*(3x-2)^(2/3)
Ans:2(14x-5)(2x+3)^3*(3x-2)^(-1/3)
A.Maths
2007-05-12 8:31 am
回答 (2)
2007-05-12 10:22 am
✔ 最佳答案
dy/dx = 4 * (2x+3)^3 * 2 * (3x-2)^(2/3) + 2/3 * (3x-2)^(-1/3) * 3 * (2x+3)^4
= 2 * (3x-2)^(-1/3) * (2x+3)^3 * [4 * (3x-2) + (2x+3)]
= 2 * (3x-2)^(-1/3) * (2x+3)^3 * (14x-5)
上面果個(大將軍)有少少出錯,第四行首項乘少左2,
不過唔知用乜software可以打到咁正,請賜教...
2007-05-12 02:24:28 補充：
人家有埋答案比你睇都會出錯???
2007-05-12 8:45 am
參考: My Maths knowledge
收錄日期: 2021-05-03 06:54:54
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https://hk.answers.yahoo.com/question/index?qid=20070512000051KK00157